numpy.core.defchararray.count¶
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numpy.core.defchararray.
count
(a, sub, start=0, end=None)[source]¶ Returns an array with the number of non-overlapping occurrences of substring sub in the range [start, end].
Calls str.count element-wise.
Parameters: a : array_like of str or unicode
sub : str or unicode
The substring to search for.
start, end : int, optional
Optional arguments start and end are interpreted as slice notation to specify the range in which to count.
Returns: out : ndarray
Output array of ints.
See also
Examples
>>> c = np.array(['aAaAaA', ' aA ', 'abBABba']) >>> c array(['aAaAaA', ' aA ', 'abBABba'], dtype='|S7') >>> np.char.count(c, 'A') array([3, 1, 1]) >>> np.char.count(c, 'aA') array([3, 1, 0]) >>> np.char.count(c, 'A', start=1, end=4) array([2, 1, 1]) >>> np.char.count(c, 'A', start=1, end=3) array([1, 0, 0])