reduceat(a, indices, axis=0, dtype=None, out=None)¶
Performs a (local) reduce with specified slices over a single axis.
For i in
ufunc.reduce(a[indices[i]:indices[i+1]]), which becomes the i-th generalized “row” parallel to axis in the final result (i.e., in a 2-D array, for example, if axis = 0, it becomes the i-th row, but if axis = 1, it becomes the i-th column). There are three exceptions to this:
i = len(indices) - 1(so for the last index),
indices[i+1] = a.shape[axis].
indices[i] >= indices[i + 1], the i-th generalized “row” is simply
indices[i] >= len(a)or
indices[i] < 0, an error is raised.
The shape of the output depends on the size of
indices, and may be larger than a (this happens if
len(indices) > a.shape[axis]).
The array to act on.
Paired indices, comma separated (not colon), specifying slices to reduce.
- axisint, optional
The axis along which to apply the reduceat.
- dtypedata-type code, optional
The type used to represent the intermediate results. Defaults to the data type of the output array if this is provided, or the data type of the input array if no output array is provided.
- outndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If not provided or None, a freshly-allocated array is returned. For consistency with
ufunc.__call__, if given as a keyword, this may be wrapped in a 1-element tuple.
Changed in version 1.13.0: Tuples are allowed for keyword argument.
The reduced values. If out was supplied, r is a reference to out.
A descriptive example:
If a is 1-D, the function ufunc.accumulate(a) is the same as
range(len(array) - 1)with a zero placed in every other element:
indices = zeros(2 * len(a) - 1),
indices[1::2] = range(1, len(a)).
Don’t be fooled by this attribute’s name: reduceat(a) is not necessarily smaller than a.
To take the running sum of four successive values:
>>> np.add.reduceat(np.arange(8),[0,4, 1,5, 2,6, 3,7])[::2] array([ 6, 10, 14, 18])
A 2-D example:
>>> x = np.linspace(0, 15, 16).reshape(4,4) >>> x array([[ 0., 1., 2., 3.], [ 4., 5., 6., 7.], [ 8., 9., 10., 11.], [12., 13., 14., 15.]])
# reduce such that the result has the following five rows: # [row1 + row2 + row3] # [row4] # [row2] # [row3] # [row1 + row2 + row3 + row4]
>>> np.add.reduceat(x, [0, 3, 1, 2, 0]) array([[12., 15., 18., 21.], [12., 13., 14., 15.], [ 4., 5., 6., 7.], [ 8., 9., 10., 11.], [24., 28., 32., 36.]])
# reduce such that result has the following two columns: # [col1 * col2 * col3, col4]
>>> np.multiply.reduceat(x, [0, 3], 1) array([[ 0., 3.], [ 120., 7.], [ 720., 11.], [2184., 15.]])