numpy.subtract¶
-
numpy.
subtract
(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'subtract'>¶ Subtract arguments, element-wise.
Parameters: x1, x2 : array_like
The arrays to be subtracted from each other.
out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
where : array_like, optional
Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
**kwargs
For other keyword-only arguments, see the ufunc docs.
Returns: y : ndarray
The difference of x1 and x2, element-wise. Returns a scalar if both x1 and x2 are scalars.
Notes
Equivalent to
x1 - x2
in terms of array broadcasting.Examples
>>> np.subtract(1.0, 4.0) -3.0
>>> x1 = np.arange(9.0).reshape((3, 3)) >>> x2 = np.arange(3.0) >>> np.subtract(x1, x2) array([[ 0., 0., 0.], [ 3., 3., 3.], [ 6., 6., 6.]])