numpy.
logical_and
Compute the truth value of x1 AND x2 element-wise.
Input arrays. If x1.shape != x2.shape, they must be broadcastable to a common shape (which becomes the shape of the output).
x1.shape != x2.shape
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
This condition is broadcast over the input. At locations where the condition is True, the out array will be set to the ufunc result. Elsewhere, the out array will retain its original value. Note that if an uninitialized out array is created via the default out=None, locations within it where the condition is False will remain uninitialized.
out=None
For other keyword-only arguments, see the ufunc docs.
Boolean result of the logical AND operation applied to the elements of x1 and x2; the shape is determined by broadcasting. This is a scalar if both x1 and x2 are scalars.
See also
logical_or
logical_not
logical_xor
bitwise_and
Examples
>>> np.logical_and(True, False) False >>> np.logical_and([True, False], [False, False]) array([False, False])
>>> x = np.arange(5) >>> np.logical_and(x>1, x<4) array([False, False, True, True, False])
The & operator can be used as a shorthand for np.logical_and on boolean ndarrays.
&
np.logical_and
>>> a = np.array([True, False]) >>> b = np.array([False, False]) >>> a & b array([False, False])