numpy.setdiff1d#
- numpy.setdiff1d(ar1, ar2, assume_unique=False)[source]#
Find the set difference of two arrays.
Return the unique values in ar1 that are not in ar2.
- Parameters
- ar1array_like
Input array.
- ar2array_like
Input comparison array.
- assume_uniquebool
If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.
- Returns
- setdiff1dndarray
1D array of values in ar1 that are not in ar2. The result is sorted when assume_unique=False, but otherwise only sorted if the input is sorted.
See also
numpy.lib.arraysetops
Module with a number of other functions for performing set operations on arrays.
Examples
>>> a = np.array([1, 2, 3, 2, 4, 1]) >>> b = np.array([3, 4, 5, 6]) >>> np.setdiff1d(a, b) array([1, 2])