numpy.emath.sqrt#
- emath.sqrt(x)[source]#
- Compute the square root of x. - For negative input elements, a complex value is returned (unlike - numpy.sqrtwhich returns NaN).- Parameters:
- xarray_like
- The input value(s). 
 
- Returns:
- outndarray or scalar
- The square root of x. If x was a scalar, so is out, otherwise an array is returned. 
 
 - See also - Examples - For real, non-negative inputs this works just like - numpy.sqrt:- >>> np.emath.sqrt(1) 1.0 >>> np.emath.sqrt([1, 4]) array([1., 2.]) - But it automatically handles negative inputs: - >>> np.emath.sqrt(-1) 1j >>> np.emath.sqrt([-1,4]) array([0.+1.j, 2.+0.j]) - Different results are expected because: floating point 0.0 and -0.0 are distinct. - For more control, explicitly use complex() as follows: - >>> np.emath.sqrt(complex(-4.0, 0.0)) 2j >>> np.emath.sqrt(complex(-4.0, -0.0)) -2j