- numpy.intersect1d(ar1, ar2, assume_unique=False, return_indices=False)#
Find the intersection of two arrays.
Return the sorted, unique values that are in both of the input arrays.
- ar1, ar2array_like
Input arrays. Will be flattened if not already 1D.
If True, the input arrays are both assumed to be unique, which can speed up the calculation. If True but
ar2are not unique, incorrect results and out-of-bounds indices could result. Default is False.
If True, the indices which correspond to the intersection of the two arrays are returned. The first instance of a value is used if there are multiple. Default is False.
New in version 1.15.0.
Sorted 1D array of common and unique elements.
The indices of the first occurrences of the common values in ar1. Only provided if return_indices is True.
The indices of the first occurrences of the common values in ar2. Only provided if return_indices is True.
Module with a number of other functions for performing set operations on arrays.
>>> np.intersect1d([1, 3, 4, 3], [3, 1, 2, 1]) array([1, 3])
To intersect more than two arrays, use functools.reduce:
>>> from functools import reduce >>> reduce(np.intersect1d, ([1, 3, 4, 3], [3, 1, 2, 1], [6, 3, 4, 2])) array()
To return the indices of the values common to the input arrays along with the intersected values:
>>> x = np.array([1, 1, 2, 3, 4]) >>> y = np.array([2, 1, 4, 6]) >>> xy, x_ind, y_ind = np.intersect1d(x, y, return_indices=True) >>> x_ind, y_ind (array([0, 2, 4]), array([1, 0, 2])) >>> xy, x[x_ind], y[y_ind] (array([1, 2, 4]), array([1, 2, 4]), array([1, 2, 4]))