numpy.char.count¶
- char.count(a, sub, start=0, end=None)[source]¶
Returns an array with the number of non-overlapping occurrences of substring sub in the range [start, end].
Calls
str.count
element-wise.- Parameters
- aarray_like of str or unicode
- substr or unicode
The substring to search for.
- start, endint, optional
Optional arguments start and end are interpreted as slice notation to specify the range in which to count.
- Returns
- outndarray
Output array of ints.
See also
Examples
>>> c = np.array(['aAaAaA', ' aA ', 'abBABba']) >>> c array(['aAaAaA', ' aA ', 'abBABba'], dtype='<U7') >>> np.char.count(c, 'A') array([3, 1, 1]) >>> np.char.count(c, 'aA') array([3, 1, 0]) >>> np.char.count(c, 'A', start=1, end=4) array([2, 1, 1]) >>> np.char.count(c, 'A', start=1, end=3) array([1, 0, 0])