numpy.average#
- numpy.average(a, axis=None, weights=None, returned=False, *, keepdims=<no value>)[source]#
Compute the weighted average along the specified axis.
- Parameters:
- aarray_like
Array containing data to be averaged. If a is not an array, a conversion is attempted.
- axisNone or int or tuple of ints, optional
Axis or axes along which to average a. The default, axis=None, will average over all of the elements of the input array. If axis is negative it counts from the last to the first axis. If axis is a tuple of ints, averaging is performed on all of the axes specified in the tuple instead of a single axis or all the axes as before.
- weightsarray_like, optional
An array of weights associated with the values in a. Each value in a contributes to the average according to its associated weight. The array of weights must be the same shape as a if no axis is specified, otherwise the weights must have dimensions and shape consistent with a along the specified axis. If weights=None, then all data in a are assumed to have a weight equal to one. The calculation is:
avg = sum(a * weights) / sum(weights)
where the sum is over all included elements. The only constraint on the values of weights is that sum(weights) must not be 0.
- returnedbool, optional
Default is False. If True, the tuple (
average
, sum_of_weights) is returned, otherwise only the average is returned. If weights=None, sum_of_weights is equivalent to the number of elements over which the average is taken.- keepdimsbool, optional
If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the original a. Note: keepdims will not work with instances of
numpy.matrix
or other classes whose methods do not support keepdims.New in version 1.23.0.
- Returns:
- retval, [sum_of_weights]array_type or double
Return the average along the specified axis. When returned is True, return a tuple with the average as the first element and the sum of the weights as the second element. sum_of_weights is of the same type as retval. The result dtype follows a general pattern. If weights is None, the result dtype will be that of a , or
float64
if a is integral. Otherwise, if weights is not None and a is non- integral, the result type will be the type of lowest precision capable of representing values of both a and weights. If a happens to be integral, the previous rules still applies but the result dtype will at least befloat64
.
- Raises:
- ZeroDivisionError
When all weights along axis are zero. See
numpy.ma.average
for a version robust to this type of error.- TypeError
When weights does not have the same shape as a, and axis=None.
- ValueError
When weights does not have dimensions and shape consistent with a along specified axis.
See also
mean
ma.average
average for masked arrays – useful if your data contains “missing” values
numpy.result_type
Returns the type that results from applying the numpy type promotion rules to the arguments.
Examples
>>> import numpy as np >>> data = np.arange(1, 5) >>> data array([1, 2, 3, 4]) >>> np.average(data) 2.5 >>> np.average(np.arange(1, 11), weights=np.arange(10, 0, -1)) 4.0
>>> data = np.arange(6).reshape((3, 2)) >>> data array([[0, 1], [2, 3], [4, 5]]) >>> np.average(data, axis=1, weights=[1./4, 3./4]) array([0.75, 2.75, 4.75]) >>> np.average(data, weights=[1./4, 3./4]) Traceback (most recent call last): ... TypeError: Axis must be specified when shapes of a and weights differ.
With
keepdims=True
, the following result has shape (3, 1).>>> np.average(data, axis=1, keepdims=True) array([[0.5], [2.5], [4.5]])
>>> data = np.arange(8).reshape((2, 2, 2)) >>> data array([[[0, 1], [2, 3]], [[4, 5], [6, 7]]]) >>> np.average(data, axis=(0, 1), weights=[[1./4, 3./4], [1., 1./2]]) array([3.4, 4.4]) >>> np.average(data, axis=0, weights=[[1./4, 3./4], [1., 1./2]]) Traceback (most recent call last): ... ValueError: Shape of weights must be consistent with shape of a along specified axis.